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3(x-2)+5=4(x+1)
We move all terms to the left:
3(x-2)+5-(4(x+1))=0
We multiply parentheses
3x-(4(x+1))-6+5=0
We calculate terms in parentheses: -(4(x+1)), so:We add all the numbers together, and all the variables
4(x+1)
We multiply parentheses
4x+4
Back to the equation:
-(4x+4)
3x-(4x+4)-1=0
We get rid of parentheses
3x-4x-4-1=0
We add all the numbers together, and all the variables
-1x-5=0
We move all terms containing x to the left, all other terms to the right
-x=5
x=5/-1
x=-5
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