3(x-2)+5=x-2(2x-3)

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Solution for 3(x-2)+5=x-2(2x-3) equation: 



3(x-2)+5=x-2(2x-3)

We move all terms to the left:

3(x-2)+5-(x-2(2x-3))=0

We multiply parentheses

3x-(x-2(2x-3))-6+5=0



We calculate terms in parentheses: -(x-2(2x-3)), so:

x-2(2x-3)

We multiply parentheses

x-4x+6

We add all the numbers together, and all the variables

-3x+6

Back to the equation:

-(-3x+6)



We add all the numbers together, and all the variables

3x-(-3x+6)-1=0

We get rid of parentheses

3x+3x-6-1=0

We add all the numbers together, and all the variables

6x-7=0

We move all terms containing x to the left, all other terms to the right

6x=7

x=7/6

x=1+1/6

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