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3(x-2)+5x=-3(x+2)+11x
We move all terms to the left:
3(x-2)+5x-(-3(x+2)+11x)=0
We add all the numbers together, and all the variables
5x+3(x-2)-(-3(x+2)+11x)=0
We multiply parentheses
5x+3x-(-3(x+2)+11x)-6=0
We calculate terms in parentheses: -(-3(x+2)+11x), so:We add all the numbers together, and all the variables
-3(x+2)+11x
We add all the numbers together, and all the variables
11x-3(x+2)
We multiply parentheses
11x-3x-6
We add all the numbers together, and all the variables
8x-6
Back to the equation:
-(8x-6)
8x-(8x-6)-6=0
We get rid of parentheses
8x-8x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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