3(x-2)+6=2+3(x-4)+2x

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Solution for 3(x-2)+6=2+3(x-4)+2x equation: 



3(x-2)+6=2+3(x-4)+2x

We move all terms to the left:

3(x-2)+6-(2+3(x-4)+2x)=0

We multiply parentheses

3x-(2+3(x-4)+2x)-6+6=0



We calculate terms in parentheses: -(2+3(x-4)+2x), so:

2+3(x-4)+2x

determiningTheFunctionDomain
3(x-4)+2x+2

We add all the numbers together, and all the variables

2x+3(x-4)+2

We multiply parentheses

2x+3x-12+2

We add all the numbers together, and all the variables

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

3x-(5x-10)=0

We get rid of parentheses

3x-5x+10=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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