3(x-2)+7=-8(x-5)

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Solution for 3(x-2)+7=-8(x-5) equation: 



3(x-2)+7=-8(x-5)

We move all terms to the left:

3(x-2)+7-(-8(x-5))=0

We multiply parentheses

3x-(-8(x-5))-6+7=0



We calculate terms in parentheses: -(-8(x-5)), so:

-8(x-5)

We multiply parentheses

-8x+40

Back to the equation:

-(-8x+40)



We add all the numbers together, and all the variables

3x-(-8x+40)+1=0

We get rid of parentheses

3x+8x-40+1=0

We add all the numbers together, and all the variables

11x-39=0

We move all terms containing x to the left, all other terms to the right

11x=39

x=39/11

x=3+6/11

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