3(x-2)+7=2-5(x+1)

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Solution for 3(x-2)+7=2-5(x+1) equation: 



3(x-2)+7=2-5(x+1)

We move all terms to the left:

3(x-2)+7-(2-5(x+1))=0

We multiply parentheses

3x-(2-5(x+1))-6+7=0



We calculate terms in parentheses: -(2-5(x+1)), so:

2-5(x+1)

determiningTheFunctionDomain
-5(x+1)+2

We multiply parentheses

-5x-5+2

We add all the numbers together, and all the variables

-5x-3

Back to the equation:

-(-5x-3)



We add all the numbers together, and all the variables

3x-(-5x-3)+1=0

We get rid of parentheses

3x+5x+3+1=0

We add all the numbers together, and all the variables

8x+4=0

We move all terms containing x to the left, all other terms to the right

8x=-4

x=-4/8

x=-1/2

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