3(x-2)+7=6+x-5

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Solution for 3(x-2)+7=6+x-5 equation: 



3(x-2)+7=6+x-5

We move all terms to the left:

3(x-2)+7-(6+x-5)=0

We add all the numbers together, and all the variables

3(x-2)-(x+1)+7=0

We multiply parentheses

3x-(x+1)-6+7=0

We get rid of parentheses

3x-x-1-6+7=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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