3(x-2)+7x=12(6x-2)

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Solution for 3(x-2)+7x=12(6x-2) equation:



3(x-2)+7x=12(6x-2)
We move all terms to the left:
3(x-2)+7x-(12(6x-2))=0
We add all the numbers together, and all the variables
7x+3(x-2)-(12(6x-2))=0
We multiply parentheses
7x+3x-(12(6x-2))-6=0
We calculate terms in parentheses: -(12(6x-2)), so:
12(6x-2)
We multiply parentheses
72x-24
Back to the equation:
-(72x-24)
We add all the numbers together, and all the variables
10x-(72x-24)-6=0
We get rid of parentheses
10x-72x+24-6=0
We add all the numbers together, and all the variables
-62x+18=0
We move all terms containing x to the left, all other terms to the right
-62x=-18
x=-18/-62
x=9/31

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