3(x-2)+7x=12(6x-2)

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Solution for 3(x-2)+7x=12(6x-2) equation: 



3(x-2)+7x=12(6x-2)

We move all terms to the left:

3(x-2)+7x-(12(6x-2))=0

We add all the numbers together, and all the variables

7x+3(x-2)-(12(6x-2))=0

We multiply parentheses

7x+3x-(12(6x-2))-6=0



We calculate terms in parentheses: -(12(6x-2)), so:

12(6x-2)

We multiply parentheses

72x-24

Back to the equation:

-(72x-24)



We add all the numbers together, and all the variables

10x-(72x-24)-6=0

We get rid of parentheses

10x-72x+24-6=0

We add all the numbers together, and all the variables

-62x+18=0

We move all terms containing x to the left, all other terms to the right

-62x=-18

x=-18/-62

x=9/31

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