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3(x-2)+x=2(2x-3)
We move all terms to the left:
3(x-2)+x-(2(2x-3))=0
We add all the numbers together, and all the variables
x+3(x-2)-(2(2x-3))=0
We multiply parentheses
x+3x-(2(2x-3))-6=0
We calculate terms in parentheses: -(2(2x-3)), so:We add all the numbers together, and all the variables
2(2x-3)
We multiply parentheses
4x-6
Back to the equation:
-(4x-6)
4x-(4x-6)-6=0
We get rid of parentheses
4x-4x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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