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3(x-2)-(6x+4)=6(2x+5)
We move all terms to the left:
3(x-2)-(6x+4)-(6(2x+5))=0
We multiply parentheses
3x-(6x+4)-(6(2x+5))-6=0
We get rid of parentheses
3x-6x-(6(2x+5))-4-6=0
We calculate terms in parentheses: -(6(2x+5)), so:We add all the numbers together, and all the variables
6(2x+5)
We multiply parentheses
12x+30
Back to the equation:
-(12x+30)
-3x-(12x+30)-10=0
We get rid of parentheses
-3x-12x-30-10=0
We add all the numbers together, and all the variables
-15x-40=0
We move all terms containing x to the left, all other terms to the right
-15x=40
x=40/-15
x=-2+2/3
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