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3(x-2)-(7x+2)=-4(3x+1)
We move all terms to the left:
3(x-2)-(7x+2)-(-4(3x+1))=0
We multiply parentheses
3x-(7x+2)-(-4(3x+1))-6=0
We get rid of parentheses
3x-7x-(-4(3x+1))-2-6=0
We calculate terms in parentheses: -(-4(3x+1)), so:We add all the numbers together, and all the variables
-4(3x+1)
We multiply parentheses
-12x-4
Back to the equation:
-(-12x-4)
-4x-(-12x-4)-8=0
We get rid of parentheses
-4x+12x+4-8=0
We add all the numbers together, and all the variables
8x-4=0
We move all terms containing x to the left, all other terms to the right
8x=4
x=4/8
x=1/2
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