3(x-2)-(x+1)4=7+(x-1)-12

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Solution for 3(x-2)-(x+1)4=7+(x-1)-12 equation: 



3(x-2)-(x+1)4=7+(x-1)-12

We move all terms to the left:

3(x-2)-(x+1)4-(7+(x-1)-12)=0

We multiply parentheses

3x-4x-(7+(x-1)-12)-6-4=0



We calculate terms in parentheses: -(7+(x-1)-12), so:

7+(x-1)-12

determiningTheFunctionDomain
(x-1)+7-12

We add all the numbers together, and all the variables

(x-1)-5

We get rid of parentheses

x-1-5

We add all the numbers together, and all the variables

x-6

Back to the equation:

-(x-6)



We add all the numbers together, and all the variables

-1x-(x-6)-10=0

We get rid of parentheses

-1x-x+6-10=0

We add all the numbers together, and all the variables

-2x-4=0

We move all terms containing x to the left, all other terms to the right

-2x=4

x=4/-2

x=-2

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