3(x-2)-1,5(2x-4)=5(0,1x+2)

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Solution for 3(x-2)-1,5(2x-4)=5(0,1x+2) equation:


3(x-2)-1,5(2x-4)=5(0,1x+2)

We simplify the equation to the form, which is simple to understand 
3(x-2)-1,5(2x-4)=5(0,1x+2)

Reorder the terms in parentheses
+(+3x-6)-1,5*(2x-4)=5*(0,1x+2)

Remove unnecessary parentheses
+3x-6-1,5+*(+2x-4+)=+5+*(,1x+2+)

Reorder the terms in parentheses
+3x-6+(-3x+6)=5*(0,1x+2)

Remove unnecessary parentheses
+3x-6-3x+6=+5+*(,1x+2+)

Reorder the terms in parentheses
+3x-6-3x+6=+( + 0.5x+10)

Remove unnecessary parentheses
+3x-6-3x+6=0.5x+10

We move all terms containing x to the left and all other terms to the right. 
+3x-3x-0.5x=+10+6-6

We simplify left and right side of the equation. 
-0.5x=+10

We divide both sides of the equation by -0.5 to get x. 
x=-20

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