3(x-2)-12=2(x-6)+8

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Solution for 3(x-2)-12=2(x-6)+8 equation: 



3(x-2)-12=2(x-6)+8

We move all terms to the left:

3(x-2)-12-(2(x-6)+8)=0

We multiply parentheses

3x-(2(x-6)+8)-6-12=0



We calculate terms in parentheses: -(2(x-6)+8), so:

2(x-6)+8

We multiply parentheses

2x-12+8

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

3x-(2x-4)-18=0

We get rid of parentheses

3x-2x+4-18=0

We add all the numbers together, and all the variables

x-14=0

We move all terms containing x to the left, all other terms to the right

x=14

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