3(x-2)-1=2(4+x)

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Solution for 3(x-2)-1=2(4+x) equation: 



3(x-2)-1=2(4+x)

We move all terms to the left:

3(x-2)-1-(2(4+x))=0

We add all the numbers together, and all the variables

3(x-2)-(2(x+4))-1=0

We multiply parentheses

3x-(2(x+4))-6-1=0



We calculate terms in parentheses: -(2(x+4)), so:

2(x+4)

We multiply parentheses

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

3x-(2x+8)-7=0

We get rid of parentheses

3x-2x-8-7=0

We add all the numbers together, and all the variables

x-15=0

We move all terms containing x to the left, all other terms to the right

x=15

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