3(x-2)-2(x+1)=2(3x-5)

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Solution for 3(x-2)-2(x+1)=2(3x-5) equation:



3(x-2)-2(x+1)=2(3x-5)
We move all terms to the left:
3(x-2)-2(x+1)-(2(3x-5))=0
We multiply parentheses
3x-2x-(2(3x-5))-6-2=0
We calculate terms in parentheses: -(2(3x-5)), so:
2(3x-5)
We multiply parentheses
6x-10
Back to the equation:
-(6x-10)
We add all the numbers together, and all the variables
x-(6x-10)-8=0
We get rid of parentheses
x-6x+10-8=0
We add all the numbers together, and all the variables
-5x+2=0
We move all terms containing x to the left, all other terms to the right
-5x=-2
x=-2/-5
x=2/5

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