3(x-2)-2(x+4)=3x-1-4(2x+1)

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Solution for 3(x-2)-2(x+4)=3x-1-4(2x+1) equation: 



3(x-2)-2(x+4)=3x-1-4(2x+1)

We move all terms to the left:

3(x-2)-2(x+4)-(3x-1-4(2x+1))=0

We multiply parentheses

3x-2x-(3x-1-4(2x+1))-6-8=0



We calculate terms in parentheses: -(3x-1-4(2x+1)), so:

3x-1-4(2x+1)

determiningTheFunctionDomain
3x-4(2x+1)-1

We multiply parentheses

3x-8x-4-1

We add all the numbers together, and all the variables

-5x-5

Back to the equation:

-(-5x-5)



We add all the numbers together, and all the variables

x-(-5x-5)-14=0

We get rid of parentheses

x+5x+5-14=0

We add all the numbers together, and all the variables

6x-9=0

We move all terms containing x to the left, all other terms to the right

6x=9

x=9/6

x=1+1/2

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