3(x-2)-2(x-3)=6(x-5)

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Solution for 3(x-2)-2(x-3)=6(x-5) equation: 



3(x-2)-2(x-3)=6(x-5)

We move all terms to the left:

3(x-2)-2(x-3)-(6(x-5))=0

We multiply parentheses

3x-2x-(6(x-5))-6+6=0



We calculate terms in parentheses: -(6(x-5)), so:

6(x-5)

We multiply parentheses

6x-30

Back to the equation:

-(6x-30)



We add all the numbers together, and all the variables

x-(6x-30)=0

We get rid of parentheses

x-6x+30=0

We add all the numbers together, and all the variables

-5x+30=0

We move all terms containing x to the left, all other terms to the right

-5x=-30

x=-30/-5

x=+6

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