3(x-2)-3(x+12)=6-2(x-2)

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Solution for 3(x-2)-3(x+12)=6-2(x-2) equation: 



3(x-2)-3(x+12)=6-2(x-2)

We move all terms to the left:

3(x-2)-3(x+12)-(6-2(x-2))=0

We multiply parentheses

3x-3x-(6-2(x-2))-6-36=0



We calculate terms in parentheses: -(6-2(x-2)), so:

6-2(x-2)

determiningTheFunctionDomain
-2(x-2)+6

We multiply parentheses

-2x+4+6

We add all the numbers together, and all the variables

-2x+10

Back to the equation:

-(-2x+10)



We add all the numbers together, and all the variables

-(-2x+10)-42=0

We get rid of parentheses

2x-10-42=0

We add all the numbers together, and all the variables

2x-52=0

We move all terms containing x to the left, all other terms to the right

2x=52

x=52/2

x=26

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