3(x-2)-4(2x+3)=42

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Solution for 3(x-2)-4(2x+3)=42 equation: 



3(x-2)-4(2x+3)=42

We move all terms to the left:

3(x-2)-4(2x+3)-(42)=0

We multiply parentheses

3x-8x-6-12-42=0

We add all the numbers together, and all the variables

-5x-60=0

We move all terms containing x to the left, all other terms to the right

-5x=60

x=60/-5

x=-12

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