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3(x-2)-4(x+3)=2(x+3)
We move all terms to the left:
3(x-2)-4(x+3)-(2(x+3))=0
We multiply parentheses
3x-4x-(2(x+3))-6-12=0
We calculate terms in parentheses: -(2(x+3)), so:We add all the numbers together, and all the variables
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
-1x-(2x+6)-18=0
We get rid of parentheses
-1x-2x-6-18=0
We add all the numbers together, and all the variables
-3x-24=0
We move all terms containing x to the left, all other terms to the right
-3x=24
x=24/-3
x=-8
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