3(x-2)-4(x-3)=(x-2)

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Solution for 3(x-2)-4(x-3)=(x-2) equation: 



3(x-2)-4(x-3)=(x-2)

We move all terms to the left:

3(x-2)-4(x-3)-((x-2))=0

We multiply parentheses

3x-4x-((x-2))-6+12=0



We calculate terms in parentheses: -((x-2)), so:

(x-2)

We get rid of parentheses

x-2

Back to the equation:

-(x-2)



We add all the numbers together, and all the variables

-1x-(x-2)+6=0

We get rid of parentheses

-1x-x+2+6=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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