3(x-2)-5(x+2)=4(3x+x)-6(2x+6)

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Solution for 3(x-2)-5(x+2)=4(3x+x)-6(2x+6) equation: 



3(x-2)-5(x+2)=4(3x+x)-6(2x+6)

We move all terms to the left:

3(x-2)-5(x+2)-(4(3x+x)-6(2x+6))=0

We add all the numbers together, and all the variables

3(x-2)-5(x+2)-(4(+4x)-6(2x+6))=0

We multiply parentheses

3x-5x-(4(+4x)-6(2x+6))-6-10=0



We calculate terms in parentheses: -(4(+4x)-6(2x+6)), so:

4(+4x)-6(2x+6)

We multiply parentheses

16x-12x-36

We add all the numbers together, and all the variables

4x-36

Back to the equation:

-(4x-36)



We add all the numbers together, and all the variables

-2x-(4x-36)-16=0

We get rid of parentheses

-2x-4x+36-16=0

We add all the numbers together, and all the variables

-6x+20=0

We move all terms containing x to the left, all other terms to the right

-6x=-20

x=-20/-6

x=3+1/3

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