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3(x-2)-5=(x-4)
We move all terms to the left:
3(x-2)-5-((x-4))=0
We multiply parentheses
3x-((x-4))-6-5=0
We calculate terms in parentheses: -((x-4)), so:We add all the numbers together, and all the variables
(x-4)
We get rid of parentheses
x-4
Back to the equation:
-(x-4)
3x-(x-4)-11=0
We get rid of parentheses
3x-x+4-11=0
We add all the numbers together, and all the variables
2x-7=0
We move all terms containing x to the left, all other terms to the right
2x=7
x=7/2
x=3+1/2
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