3(x-2)-5=2-(x+1)

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Solution for 3(x-2)-5=2-(x+1) equation: 



3(x-2)-5=2-(x+1)

We move all terms to the left:

3(x-2)-5-(2-(x+1))=0

We multiply parentheses

3x-(2-(x+1))-6-5=0



We calculate terms in parentheses: -(2-(x+1)), so:

2-(x+1)

determiningTheFunctionDomain
-(x+1)+2

We get rid of parentheses

-x-1+2

We add all the numbers together, and all the variables

-1x+1

Back to the equation:

-(-1x+1)



We add all the numbers together, and all the variables

3x-(-1x+1)-11=0

We get rid of parentheses

3x+1x-1-11=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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