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3(x-2)-6=-3(-6x+1)-9x
We move all terms to the left:
3(x-2)-6-(-3(-6x+1)-9x)=0
We multiply parentheses
3x-(-3(-6x+1)-9x)-6-6=0
We calculate terms in parentheses: -(-3(-6x+1)-9x), so:We add all the numbers together, and all the variables
-3(-6x+1)-9x
We add all the numbers together, and all the variables
-9x-3(-6x+1)
We multiply parentheses
-9x+18x-3
We add all the numbers together, and all the variables
9x-3
Back to the equation:
-(9x-3)
3x-(9x-3)-12=0
We get rid of parentheses
3x-9x+3-12=0
We add all the numbers together, and all the variables
-6x-9=0
We move all terms containing x to the left, all other terms to the right
-6x=9
x=9/-6
x=-1+1/2
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