3(x-2)-6=8x+6(1-x)

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Solution for 3(x-2)-6=8x+6(1-x) equation: 



3(x-2)-6=8x+6(1-x)

We move all terms to the left:

3(x-2)-6-(8x+6(1-x))=0

We add all the numbers together, and all the variables

3(x-2)-(8x+6(-1x+1))-6=0

We multiply parentheses

3x-(8x+6(-1x+1))-6-6=0



We calculate terms in parentheses: -(8x+6(-1x+1)), so:

8x+6(-1x+1)

We multiply parentheses

8x-6x+6

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

3x-(2x+6)-12=0

We get rid of parentheses

3x-2x-6-12=0

We add all the numbers together, and all the variables

x-18=0

We move all terms containing x to the left, all other terms to the right

x=18

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