3(x-2)-7(x+1)=-2(2x+1)-3(x+2)

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Solution for 3(x-2)-7(x+1)=-2(2x+1)-3(x+2) equation: 



3(x-2)-7(x+1)=-2(2x+1)-3(x+2)

We move all terms to the left:

3(x-2)-7(x+1)-(-2(2x+1)-3(x+2))=0

We multiply parentheses

3x-7x-(-2(2x+1)-3(x+2))-6-7=0



We calculate terms in parentheses: -(-2(2x+1)-3(x+2)), so:

-2(2x+1)-3(x+2)

We multiply parentheses

-4x-3x-2-6

We add all the numbers together, and all the variables

-7x-8

Back to the equation:

-(-7x-8)



We add all the numbers together, and all the variables

-4x-(-7x-8)-13=0

We get rid of parentheses

-4x+7x+8-13=0

We add all the numbers together, and all the variables

3x-5=0

We move all terms containing x to the left, all other terms to the right

3x=5

x=5/3

x=1+2/3

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