3(x-2)-8(x+4)=-2(x+19)

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Solution for 3(x-2)-8(x+4)=-2(x+19) equation: 



3(x-2)-8(x+4)=-2(x+19)

We move all terms to the left:

3(x-2)-8(x+4)-(-2(x+19))=0

We multiply parentheses

3x-8x-(-2(x+19))-6-32=0



We calculate terms in parentheses: -(-2(x+19)), so:

-2(x+19)

We multiply parentheses

-2x-38

Back to the equation:

-(-2x-38)



We add all the numbers together, and all the variables

-5x-(-2x-38)-38=0

We get rid of parentheses

-5x+2x+38-38=0

We add all the numbers together, and all the variables

-3x=0

x=0/-3

x=0

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