3(x-2)-8=4(1+x)+5

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Solution for 3(x-2)-8=4(1+x)+5 equation: 



3(x-2)-8=4(1+x)+5

We move all terms to the left:

3(x-2)-8-(4(1+x)+5)=0

We add all the numbers together, and all the variables

3(x-2)-(4(x+1)+5)-8=0

We multiply parentheses

3x-(4(x+1)+5)-6-8=0



We calculate terms in parentheses: -(4(x+1)+5), so:

4(x+1)+5

We multiply parentheses

4x+4+5

We add all the numbers together, and all the variables

4x+9

Back to the equation:

-(4x+9)



We add all the numbers together, and all the variables

3x-(4x+9)-14=0

We get rid of parentheses

3x-4x-9-14=0

We add all the numbers together, and all the variables

-1x-23=0

We move all terms containing x to the left, all other terms to the right

-x=23

x=23/-1

x=-23

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