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3(x-2)-x=2(x-3)
We move all terms to the left:
3(x-2)-x-(2(x-3))=0
We add all the numbers together, and all the variables
-1x+3(x-2)-(2(x-3))=0
We multiply parentheses
-1x+3x-(2(x-3))-6=0
We calculate terms in parentheses: -(2(x-3)), so:We add all the numbers together, and all the variables
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
2x-(2x-6)-6=0
We get rid of parentheses
2x-2x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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