3(x-2)/2=3(x+3)/7

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Solution for 3(x-2)/2=3(x+3)/7 equation: 



3(x-2)/2=3(x+3)/7

We move all terms to the left:

3(x-2)/2-(3(x+3)/7)=0

We calculate fractions


3x/()+(-(3(x+3)*2)/()=0



We calculate terms in parentheses: +(-(3(x+3)*2)/(), so:

-(3(x+3)*2)/(

We multiply all the terms by the denominator


-(3(x+3)*2)



We calculate terms in parentheses: -(3(x+3)*2), so:

3(x+3)*2

We multiply parentheses

6x+18

Back to the equation:

-(6x+18)



We get rid of parentheses

-6x-18

Back to the equation:

+(-6x-18)



We get rid of parentheses

3x/()-6x-18=0

We multiply all the terms by the denominator


3x-6x*()-18*()=0

We add all the numbers together, and all the variables

3x-6x*()=0

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