3(x-2)=(2x-4)+9

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Solution for 3(x-2)=(2x-4)+9 equation: 



3(x-2)=(2x-4)+9

We move all terms to the left:

3(x-2)-((2x-4)+9)=0

We multiply parentheses

3x-((2x-4)+9)-6=0



We calculate terms in parentheses: -((2x-4)+9), so:

(2x-4)+9

We get rid of parentheses

2x-4+9

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We get rid of parentheses

3x-2x-5-6=0

We add all the numbers together, and all the variables

x-11=0

We move all terms containing x to the left, all other terms to the right

x=11

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