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3(x-2)=(x+3)
We move all terms to the left:
3(x-2)-((x+3))=0
We multiply parentheses
3x-((x+3))-6=0
We calculate terms in parentheses: -((x+3)), so:We get rid of parentheses
(x+3)
We get rid of parentheses
x+3
Back to the equation:
-(x+3)
3x-x-3-6=0
We add all the numbers together, and all the variables
2x-9=0
We move all terms containing x to the left, all other terms to the right
2x=9
x=9/2
x=4+1/2
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