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3(x-2)=(x-3)
We move all terms to the left:
3(x-2)-((x-3))=0
We multiply parentheses
3x-((x-3))-6=0
We calculate terms in parentheses: -((x-3)), so:We get rid of parentheses
(x-3)
We get rid of parentheses
x-3
Back to the equation:
-(x-3)
3x-x+3-6=0
We add all the numbers together, and all the variables
2x-3=0
We move all terms containing x to the left, all other terms to the right
2x=3
x=3/2
x=1+1/2
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