3(x-2)=-2(4-x)+5

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Solution for 3(x-2)=-2(4-x)+5 equation:



3(x-2)=-2(4-x)+5
We move all terms to the left:
3(x-2)-(-2(4-x)+5)=0
We add all the numbers together, and all the variables
3(x-2)-(-2(-1x+4)+5)=0
We multiply parentheses
3x-(-2(-1x+4)+5)-6=0
We calculate terms in parentheses: -(-2(-1x+4)+5), so:
-2(-1x+4)+5
We multiply parentheses
2x-8+5
We add all the numbers together, and all the variables
2x-3
Back to the equation:
-(2x-3)
We get rid of parentheses
3x-2x+3-6=0
We add all the numbers together, and all the variables
x-3=0
We move all terms containing x to the left, all other terms to the right
x=3

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