3(x-2)=-2(4-x)+5

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Solution for 3(x-2)=-2(4-x)+5 equation: 



3(x-2)=-2(4-x)+5

We move all terms to the left:

3(x-2)-(-2(4-x)+5)=0

We add all the numbers together, and all the variables

3(x-2)-(-2(-1x+4)+5)=0

We multiply parentheses

3x-(-2(-1x+4)+5)-6=0



We calculate terms in parentheses: -(-2(-1x+4)+5), so:

-2(-1x+4)+5

We multiply parentheses

2x-8+5

We add all the numbers together, and all the variables

2x-3

Back to the equation:

-(2x-3)



We get rid of parentheses

3x-2x+3-6=0

We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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