3(x-2)=-5(x-1)+5

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Solution for 3(x-2)=-5(x-1)+5 equation:



3(x-2)=-5(x-1)+5
We move all terms to the left:
3(x-2)-(-5(x-1)+5)=0
We multiply parentheses
3x-(-5(x-1)+5)-6=0
We calculate terms in parentheses: -(-5(x-1)+5), so:
-5(x-1)+5
We multiply parentheses
-5x+5+5
We add all the numbers together, and all the variables
-5x+10
Back to the equation:
-(-5x+10)
We get rid of parentheses
3x+5x-10-6=0
We add all the numbers together, and all the variables
8x-16=0
We move all terms containing x to the left, all other terms to the right
8x=16
x=16/8
x=2

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