3(x-2)=12(x+1)=

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Solution for 3(x-2)=12(x+1)= equation: 



3(x-2)=12(x+1)=

We move all terms to the left:

3(x-2)-(12(x+1))=0

We multiply parentheses

3x-(12(x+1))-6=0



We calculate terms in parentheses: -(12(x+1)), so:

12(x+1)

We multiply parentheses

12x+12

Back to the equation:

-(12x+12)



We get rid of parentheses

3x-12x-12-6=0

We add all the numbers together, and all the variables

-9x-18=0

We move all terms containing x to the left, all other terms to the right

-9x=18

x=18/-9

x=-2

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