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3(x-2)=2(2x+6)
We move all terms to the left:
3(x-2)-(2(2x+6))=0
We multiply parentheses
3x-(2(2x+6))-6=0
We calculate terms in parentheses: -(2(2x+6)), so:We get rid of parentheses
2(2x+6)
We multiply parentheses
4x+12
Back to the equation:
-(4x+12)
3x-4x-12-6=0
We add all the numbers together, and all the variables
-1x-18=0
We move all terms containing x to the left, all other terms to the right
-x=18
x=18/-1
x=-18
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