3(x-2)=2(x+4)-5

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Solution for 3(x-2)=2(x+4)-5 equation: 



3(x-2)=2(x+4)-5

We move all terms to the left:

3(x-2)-(2(x+4)-5)=0

We multiply parentheses

3x-(2(x+4)-5)-6=0



We calculate terms in parentheses: -(2(x+4)-5), so:

2(x+4)-5

We multiply parentheses

2x+8-5

We add all the numbers together, and all the variables

2x+3

Back to the equation:

-(2x+3)



We get rid of parentheses

3x-2x-3-6=0

We add all the numbers together, and all the variables

x-9=0

We move all terms containing x to the left, all other terms to the right

x=9

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