3(x-2)=2(x-3)+

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Solution for 3(x-2)=2(x-3)+ equation: 



3(x-2)=2(x-3)+

We move all terms to the left:

3(x-2)-(2(x-3)+)=0

We multiply parentheses

3x-(2(x-3)+)-6=0



We calculate terms in parentheses: -(2(x-3)+), so:

2(x-3)+

We add all the numbers together, and all the variables

2(x-3)

We multiply parentheses

2x-6

Back to the equation:

-(2x-6)



We get rid of parentheses

3x-2x+6-6=0

We add all the numbers together, and all the variables

x=0

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