3(x-2)=2x+1-3(-5x-3)

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Solution for 3(x-2)=2x+1-3(-5x-3) equation: 



3(x-2)=2x+1-3(-5x-3)

We move all terms to the left:

3(x-2)-(2x+1-3(-5x-3))=0

We multiply parentheses

3x-(2x+1-3(-5x-3))-6=0



We calculate terms in parentheses: -(2x+1-3(-5x-3)), so:

2x+1-3(-5x-3)

determiningTheFunctionDomain
2x-3(-5x-3)+1

We multiply parentheses

2x+15x+9+1

We add all the numbers together, and all the variables

17x+10

Back to the equation:

-(17x+10)



We get rid of parentheses

3x-17x-10-6=0

We add all the numbers together, and all the variables

-14x-16=0

We move all terms containing x to the left, all other terms to the right

-14x=16

x=16/-14

x=-1+1/7

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