3(x-2)=2x+10

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Solution for 3(x-2)=2x+10 equation: 



3(x-2)=2x+10

We move all terms to the left:

3(x-2)-(2x+10)=0

We multiply parentheses

3x-(2x+10)-6=0

We get rid of parentheses

3x-2x-10-6=0

We add all the numbers together, and all the variables

x-16=0

We move all terms containing x to the left, all other terms to the right

x=16

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