3(x-2)=2x+10

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Solution for 3(x-2)=2x+10 equation:



3(x-2)=2x+10
We move all terms to the left:
3(x-2)-(2x+10)=0
We multiply parentheses
3x-(2x+10)-6=0
We get rid of parentheses
3x-2x-10-6=0
We add all the numbers together, and all the variables
x-16=0
We move all terms containing x to the left, all other terms to the right
x=16

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