3(x-2)=3(x+4)-18

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Solution for 3(x-2)=3(x+4)-18 equation:



3(x-2)=3(x+4)-18
We move all terms to the left:
3(x-2)-(3(x+4)-18)=0
We multiply parentheses
3x-(3(x+4)-18)-6=0
We calculate terms in parentheses: -(3(x+4)-18), so:
3(x+4)-18
We multiply parentheses
3x+12-18
We add all the numbers together, and all the variables
3x-6
Back to the equation:
-(3x-6)
We get rid of parentheses
3x-3x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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