3(x-2)=3(x+4)-18

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Solution for 3(x-2)=3(x+4)-18 equation: 



3(x-2)=3(x+4)-18

We move all terms to the left:

3(x-2)-(3(x+4)-18)=0

We multiply parentheses

3x-(3(x+4)-18)-6=0



We calculate terms in parentheses: -(3(x+4)-18), so:

3(x+4)-18

We multiply parentheses

3x+12-18

We add all the numbers together, and all the variables

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

3x-3x+6-6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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