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3(x-2)=3(x-4)
We move all terms to the left:
3(x-2)-(3(x-4))=0
We multiply parentheses
3x-(3(x-4))-6=0
We calculate terms in parentheses: -(3(x-4)), so:We get rid of parentheses
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
3x-3x+12-6=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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