3(x-2)=3x+2-2(-8x-3)

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Solution for 3(x-2)=3x+2-2(-8x-3) equation: 



3(x-2)=3x+2-2(-8x-3)

We move all terms to the left:

3(x-2)-(3x+2-2(-8x-3))=0

We multiply parentheses

3x-(3x+2-2(-8x-3))-6=0



We calculate terms in parentheses: -(3x+2-2(-8x-3)), so:

3x+2-2(-8x-3)

determiningTheFunctionDomain
3x-2(-8x-3)+2

We multiply parentheses

3x+16x+6+2

We add all the numbers together, and all the variables

19x+8

Back to the equation:

-(19x+8)



We get rid of parentheses

3x-19x-8-6=0

We add all the numbers together, and all the variables

-16x-14=0

We move all terms containing x to the left, all other terms to the right

-16x=14

x=14/-16

x=-7/8

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