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3(x-2)=4(1-x)
We move all terms to the left:
3(x-2)-(4(1-x))=0
We add all the numbers together, and all the variables
3(x-2)-(4(-1x+1))=0
We multiply parentheses
3x-(4(-1x+1))-6=0
We calculate terms in parentheses: -(4(-1x+1)), so:We get rid of parentheses
4(-1x+1)
We multiply parentheses
-4x+4
Back to the equation:
-(-4x+4)
3x+4x-4-6=0
We add all the numbers together, and all the variables
7x-10=0
We move all terms containing x to the left, all other terms to the right
7x=10
x=10/7
x=1+3/7
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