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3(x-2)=4(2x+5)
We move all terms to the left:
3(x-2)-(4(2x+5))=0
We multiply parentheses
3x-(4(2x+5))-6=0
We calculate terms in parentheses: -(4(2x+5)), so:We get rid of parentheses
4(2x+5)
We multiply parentheses
8x+20
Back to the equation:
-(8x+20)
3x-8x-20-6=0
We add all the numbers together, and all the variables
-5x-26=0
We move all terms containing x to the left, all other terms to the right
-5x=26
x=26/-5
x=-5+1/5
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