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3(x-2)=4(3+1/2x
We move all terms to the left:
3(x-2)-(4(3+1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3(x-2)-(4(1/2x+3)=0
We multiply parentheses
3x-(4(1/2x+3)-6=0
We multiply all the terms by the denominator
3x*2x+3)-6-(4(1=0
We add all the numbers together, and all the variables
3x*2x=0
Wy multiply elements
6x^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{12}=0$
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