3(x-2)=4(x+1)+2

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Solution for 3(x-2)=4(x+1)+2 equation: 



3(x-2)=4(x+1)+2

We move all terms to the left:

3(x-2)-(4(x+1)+2)=0

We multiply parentheses

3x-(4(x+1)+2)-6=0



We calculate terms in parentheses: -(4(x+1)+2), so:

4(x+1)+2

We multiply parentheses

4x+4+2

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We get rid of parentheses

3x-4x-6-6=0

We add all the numbers together, and all the variables

-1x-12=0

We move all terms containing x to the left, all other terms to the right

-x=12

x=12/-1

x=-12

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